Pcores were 5.5 to 5.3 and max Vcore was 1.4V. Just benched mine with a maximus extreme, 12900k and highest temp was 80C in HWInfo64. For example, to create a new circuit called CW061031.CIR: MacSpice 8 -> edit CW061031.
You can use the MacSpice edit command to edit the current source file, or to create a new one. Therefore, using Ohm’s law (V= I x R), V 1 = 5 x I, V 2 = 10 x I and V 3 = 15 x IĪnd the voltage across 15 Ω resistor (V 3) = 15 x I = 15 V x 0.1A = 1.5 Vįrom the above example, we can see that, using the Kirchhoff’s voltage law, it is possible to find the current and the voltage across any element in the electrical circuit. I’m using AI OC setting in the bios with a 100mV negative offset to decrease the peak voltage. Record the values of node voltages and branch currents found by MacSpice in your notebook and check they agree with the values you calculated above. Let’s say the current in the circuit is I. Since all the elements are connected in series, the current flowing through each element is the same. Since, moving in the clockwise direction, there is a rise in potential only across 5V voltage source and there is a drop in the potential across remaining elements. Let’s say the voltage drop across 5 Ω, 10 Ω, and 15 Ω resistor are V1, V2, and V3 respectively. In this case, the first source is swept over its range for each value of the second source. A second source ( SRC2) may optionally be specified with associated sweep parameters. Exampleįind the current I and the voltage across 15 Ω resistor.įirst, let’s denote the voltages across each element. The first example causes the value of the voltage source VIN to be swept from 0.25 volts to 5.0 volts in increments of 0.25 volts. That means KVL is the law of conservation of energy.
Or it can be said that the energy supplied by the voltage source is equal to the energy dissipated across three elements.